Web24 mrt. 2024 · Rock beats scissors and loses to paper. Make a closed fist to throw a rock out. This powerful play is strong enough to break the fragile scissors, but can’t fight its … Web13 jul. 2016 · def SPC(): computer_choice = choice( ['stone', 'paper', 'scissor'] ) computer_choosed = "Computer choosed %s" % computer_choice print "Make an …

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Web1. An easier way to solve this is to make two dictionaries for win and lose conditions, then assign user input as the keys and computer input as the values in the dictionary. rps_win= {'rock':'scissor','paper':'rock','scissor':'paper'} rps_lose= {'rock':'paper','paper':'scissor','scissor':'rock'} Then check if that user-computer pair is … Web29 mrt. 2024 · Find a partner and decide how many rounds you’ll play. Rock, paper, scissors is played with two people, so find a partner to play with before you begin. Then, choose an odd number of rounds that you’ll play. By choosing an odd number, you’ll avoid … Choose Your Newsletters. Sign up for one, two, or all of our weekly digests, chock … medical terminology for dummies download

Python rock paper scissors score counter - Stack Overflow

WebPaper covers rock. You win! Make your move Web27 jun. 2024 · The simplest way to check for the winner of rock paper scissors in Python is by referring to the cell corresponding to each player’s input. Below is the matrix for the traditional game: Win-Lose Matrix The non-negative values of the matrix denote the winner of the corresponding inputs. Let us take an example, to completely comprehend the matrix. Web28 nov. 2013 · If you wrap 3 around to 1 (using %) then the winner is always 1 greater than the loser. This approach is more natural when you use 0-2, in which case we would use (ComputerIn+1)%3. I came up with my answer by subbing ComputerIn with ComputerIn-1 and UserInput with UserInput-1 and simplifying the expression. light show speakers vine